(a) Py = 2*M*g (since vertical forces must balance)

(b) sum the moments about the pivot: TLsin = Mg(3L/4)cos Mg(L/2)cos

L cancels;

T = (Mg*cos/sin)(3/4 1/2) = (Mg / tan)(5/4) = 5Mg / 4tan

(c) Px = T

(a) Py = 2*M*g (since vertical forces must balance)

(b) sum the moments about the pivot: TLsin = Mg(3L/4)cos Mg(L/2)cos

L cancels;

T = (Mg*cos/sin)(3/4 1/2) = (Mg / tan)(5/4) = 5Mg / 4tan

(c) Px = T

EDIT: I looked at your cool see-saw problem, but it is not possible to do without the diagram.

This post is last updated on hrtanswers.com at Date : 1st of September – 2022