How does sinxcosx = (1/2)sin2x [Solved]

ok, weve: sin x cos x dx (sin x cos x) dx (sin (2x)/2) dx a million/8sin (2x) dx a million/8(sin (2x)) sin (2x) dx a million/8(a million- cos (2x)) sin (2x) dx a million/8sin (2x) dx a million/8cos (2x) sin (2x) dx -cos (2x)/sixteen a million/8 cos (2x) sin (2x) dx u=cos (2x), du=-2 sin (2x) dx, sin (2x) dx=-du/2 -cos (2x)/sixteen a million/sixteen u du -cos (2x)/sixteen u/40 8 C -cos (2x)/sixteen cos (2x)/40 8 C

Take (cos(x) i sin(x))^n = cos(nx) isin(nx)

hum maybe u should try pushing 2nd then sin or cos

cos(2x) = cos^2(x) sin^2(x)
sin(2x) = 2cos(x)sin(x)
(1/2)sin(2x) = cos(x)sin(x)

hum maybe u should try pushing 2nd then sin or cos

ok, weve: sin x cos x dx (sin x cos x) dx (sin (2x)/2) dx a million/8sin (2x) dx a million/8(sin (2x)) sin (2x) dx a million/8(a million- cos (2x)) sin (2x) dx a million/8sin (2x) dx a million/8cos (2x) sin (2x) dx -cos (2x)/sixteen a million/8 cos (2x) sin (2x) dx u=cos (2x), du=-2 sin (2x) dx, sin (2x) dx=-du/2 -cos (2x)/sixteen a million/sixteen u du -cos (2x)/sixteen u/40 8 C -cos (2x)/sixteen cos (2x)/40 8 C

sin 2x=sin(x x)=sin x cos x cos x sinx=2sin x cos x

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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