How many calories are required to raise the temperature of 105 g of water from 30.0C to 70.0C [Solved]

Specific heat capacity for water is 1 cal/gram C

H = mcT = 105 g * 1 * 40.0 = 4.20 * 10^3 calories

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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