How many grams of KBr are required to make 650. mL of a 0.115 M KBr solution [Solved]

so, 0.115 mol/L = m/(119 g/mol x 0.65 L).

Ok, you need the use the formula of molarity here:

so, 0.115 mol/L = m/(119 g/mol x 0.65 L).

molar concentration= (mass of KBr)/(molar mass of KBr x volume of solution in liters). This is true for every solution!

From here its simple math to calculate m.
m = 0.115 x 77.35 = 8.9 g (answer C)

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

Get Answer for  Which of the following european countries has a marine west coast climate [Solved]