How many milliliters of 0.400 M NaOH are required to completely neutralize 20.0 mL of 0.200 M HCl [Solved]

moles HCl = 0.0200 L x 0.200 M=0.00400
moles NaOH = 0.00400
Volume of NaOH = 0.00400/ 0.400 M=0.0100 L = 10.0 mL

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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