How many oxygen atoms are in 1.30g of quartz [Solved]

Pure quartz has a molecular compostion of SiO2. The mol weight of SiO2 is
2 * 16 28 = 60 g/mol
mols of SiO2 = 1.30 / 60 = 0.0217 mol.
Number of O2 atoms = 2 * 0.0217 * 6.022 x 10^27 = 2.61 x 10^26

Pure quartz consist of SiO2. The molecular weight of SiO2 is actually
Si= 28
O2= 32
combined this gives you a total of 60 g/mol
so you would then take 1.30g / 60 g/mol = .02167

so since there are 2 Oxygen atoms then you multiply= .02167 x 2= .04333

1.30gSiO2 x [32gO / 60gSiO2] x [6.02E23atoms O / 16gO] =

Source(s): Chem Major.

1.30gSiO2 x [32gO / 60gSiO2] x [6.02E23atoms O / 16gO] =

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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