RE:

How to factor x^2 16

I know that x^2-16 is a perfect square but 16 will not factor. I believe there is a formula similar to the cube root formula but not sure Maybe I am just over thinking this. Thanks for the help

If you are aware of i

where i =sqrt(-1)

then the roots are (x 4i) and (x-4i)

Remember when using the formula

If you are aware of i

where i =sqrt(-1)

then the roots are (x 4i) and (x-4i)

this is a trick question. The answer is that it cant factor further so it is undefined.

RE:

How to factor x^2 16

I know that x^2-16 is a perfect square but 16 will not factor. I believe there is a formula similar to the cube root formula but not sure Maybe I am just over thinking this. Thanks for the help

Answer 7

Remember when using the formula

a=1

b=0

c=16

There are no REAL distinct roots for that. If you were to subtract 16, you would be taking a negative square root, which is not allowed. If you did, you would be getting into a branch of mathematics called imaginary numbers (i). For your purposes, there are no roots.

There are no REAL distinct roots for that. If you were to subtract 16, you would be taking a negative square root, which is not allowed. If you did, you would be getting into a branch of mathematics called imaginary numbers (i). For your purposes, there are no roots.

Answer 7

you need to think what time 16 and add or subtract 0

(4)(4)= 16

4 4= 8

This is case they will be give you image number. Thats not real number.

(x^2-16)

it is work because

(-4)(4)= -16

-4 4=0

If you are aware of i

where i =sqrt(-1)

then the roots are (x 4i) and (x-4i)

If you are aware of i

where i =sqrt(-1)

then the roots are (x 4i) and (x-4i)

This post is last updated on hrtanswers.com at Date : 1st of September – 2022