If 25.0g of MgSO47H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain [Solved]

25.0g MgSO47H2O x ( 1 mol MgSO47H2O / 246.4g MgSO47H2O) x (1 mol MgSO4 / 1 mol MgSO47H2O) x (120.4 g MgSO4 / 1 mol MgSO4) = 12.2 g MgSO4

Dehydration of magnesium sulfate heptahydrate:
MgSO47H2O(s) -> MgSO4(s) 7H2O(l)
25.0g .g

Dehydration of magnesium sulfate heptahydrate:
MgSO47H2O(s) -> MgSO4(s) 7H2O(l)
25.0g .g

Mgso4 7h2o

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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