if the graph of f(x)= 2x^2=k/x has a point of inflection at x=-1, the the value of k is [Solved]

f(-1) = 0 ==> k = 2

f'(x) = 4x k/x^2

I would assume that you meant f(x)= 2x^2 k/x

f(-1) = 0 ==> k = 2

f(-1) = 0 ==> k = 2

f'(x) = 4x k/x^2

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