In hydrogen iodide __________________ are the most important intermolecular forces. [Solved]

Yes, Id agree with dipole-dipole forces

Hydrogen iodide .. Dipole-dipole the most important intermolecular attraction Heavens, no.

Hydrogen iodide .. Dipole-dipole the most important intermolecular attraction Heavens, no.

The HI bond is polar, but the net dipole moment is only 0.38D, not a very polar molecule. The most important attractions between HI molecules are London dispersion forces. The strength of London dispersion forces is proportional to the polarizability of the molecule, which in turn, depends on the total number of electrons and the area over which they are spread. HI has 54 electrons and is larger than any of the other HX molecules. Therefore, the London dispersion forces are greater than either the Keesom forces (dipole-dipole attraction) or Debye forces (induced attraction).

Compare the HX compounds:
.. dipole moment .. boiling pt.
HF . 1.86D .. 20C Hydrogen bonding
HCl 1.05D . -85C
HBr 0.82D . -67C
HI 0.38D . -35C

Notice has HCl and HBr have lower boiling points, but more polar bonds than HI. Clearly the dipole-dipole attraction cant account for that. If the boiling point was a function of the dipole-dipole attraction the HCl would have the highest boiling point of HCl, HBr and HI, but it instead has the lowest. Therefore, the dipole-dipole attraction is less important than the London dispersion forces.
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Notice has HCl and HBr have lower boiling points, but more polar bonds than HI. Clearly the dipole-dipole attraction cant account for that. If the boiling point was a function of the dipole-dipole attraction the HCl would have the highest boiling point of HCl, HBr and HI, but it instead has the lowest. Therefore, the dipole-dipole attraction is less important than the London dispersion forces.
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