O2(g) effuses at a rate that is ______ times that of Kr(g) under the same conditions. [Solved]

by

rate O2/ rate Kr=

from grahams law
.. rate 1 / rate 2 = sqrt (molar mass 2 / molar mass 1)

from grahams law
.. rate 1 / rate 2 = sqrt (molar mass 2 / molar mass 1)

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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