If the create has a mass of 90kg and is 1.6 m tall and 0.80 m in depth and width, whats the minimal power wanted to make the crate begin tipping (Assume the middle of mass of the crate is at its middle and static friction nice sufficient to forestall slipping.)

F > 0.8 m *90 kg * 9.8 m/s^2 / (2 * 1.6 m)

F > 220.5 N

F > 0.8 m *90 kg * 9.8 m/s^2 / (2 * 1.6 m)

F > 220.5 N

F * h > (1/2) w * mg

F > wmg/(2h)

Good Luck

The second wanted is 90*9.8*0.4. Your second arm is 0.8 m so you have to apply a power of 90*9.8*0.4/0.8 N. That is 441 N.

This post is last updated on hrtanswers.com at Date : 1st of September – 2022