Physics with calc help please [Solved]

A string is wrapped around a pulley with a radius of 2.0 cm and no appreciable friction in its axle. The pulley is initially not turning. A constant force of 50 N is applied to the string, which does not slip, causing the pulley to rotate and the string to unwind. If the string unwinds 1.2 m in 4.9 s, what is the moment of inertia of the pulley

a = 2x/t = 2*1.2/4.9 = 0.10 m/s
= a/R = a/0.02 = 5.0 rad/sec
Torque Q = 50*0.02 = 1 Nm

I = Q/ = 0.2 kgm

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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