27^(2/3) = 9

lasts :

just foil as you would normally, keeping in mind that i^2 = -1.

so, x^(8/15)

firsts:

Answer 6

listen in class

-48 44i

Answer 7

listen in class

4 * -7 i = -28 i

-48-44i

(4 8i)(2 7i)

8 28i -16i 56

64 44i

-13 12i

The FOIL technique. First, outdoors, interior, final. in simple terms like numerous different polynomial simplification. of direction i = (-a million). So it is going to look like this: First outdoors interior final (4)(5) (4)(-7i) (3i)(5) (3i)(-7i) = 20 28i 15i 21i = 20 13i 21 = 40-one 13i (simplified)

27^-(2/3) = 1/9

i^31 = i

(-8 8i)-(5 -4i)

40 32i -40i – 32

72 -8i

= 8 44 i 56

so, 1 * i^3 = i^3 but i^2 = -1 so i^3 = -1i

so, x^(8/15)

The negative exponent simply puts the number 27^(2/3) (no more negative exponent) as the denominator of a unit fraction (1 as the numerator)

= 8 44 i 56

27^-(2/3) = 1/9

i^31 = i

(-8 8i)-(5 -4i)

40 32i -40i – 32

72 -8i

firsts:

-48-44i

just foil as you would normally, keeping in mind that i^2 = -1.

firsts:

4 * 2 = 8

= 48 44 i

Answer 7

1) Multiply the terms using F.O.I.L. (First, Outer, Inner, Last), and know that -1 = i

( 4 8i ) ( 2 7i )

= 42 4x-7i -8ix2 -8i x -7i

= 8 28i -16i 56i

= 8 44i 56(-1)

= 8 44i 56x-1

= 8 44i 56

= -48 44i

2) 27^-(2/3)

Anything to the power of a negative number is the same as one over the same number to the positive power:

= 1 / 27^(2/3)

= 1 / 27^(2 * )

= 1 / (27^2 ^ )

= 1 / (729 ^ )

Anything to the power of a fraction is a root. To the power is a square root; to the power is a cube root.

= 1 / 729

= 1 / 9

3) i=-1

That means that i = (-1) = -1

That means that i= (-1) = (-1) = 1

i^31 = i^(4*7 2 1) = i^(4*7)ii = i^4^7 i i = 1^7 x -1 x i = 1 x -i = -i

4) Expand:

= -8 8i -5 4i

= -13 12i

5) If you raise a power to another power, you can simply multiply the exponents together:

x ^ 2/3 ^ 4/5

= x ^ [ (2*4)/(3*5) ]

= x ^ 8/15

27^(2/3) = 9

2 * -8 i = -16 i

4 * 2 = 8

-8 5 and 8i (-4i)

4) Expand:

= -8 8i -5 4i

= -13 12i

(4 8i)(2 7i)

8 28i -16i 56

64 44i

-1i is the simplified answer.

= 48 44 i

so, 1 * i^3 = i^3 but i^2 = -1 so i^3 = -1i

lasts :

8 i * 7 i = 56 i ^2 = 56.

Answer 6

outer:

8 16 i 28 i 56

(4-8i)(2-7i)

3) i=-1

That means that i = (-1) = -1

That means that i= (-1) = (-1) = 1

i^31 = i^(4*7 2 1) = i^(4*7)ii = i^4^7 i i = 1^7 x -1 x i = 1 x -i = -i

Answer 6

2 * -8 i = -16 i

(4 8i)(2 7i)

8 28i -16i 56

64 44i

27^-(2/3) = 1/9

i^31 = i

(-8 8i)-(5 -4i)

40 32i -40i – 32

72 -8i

i^31 = i^28 * i^3 (since 28 is the highest multiple of 4, the first 28 is that you multiply together end up giving you 1.

27^-(2/3) = 1/9

i^31 = i

(-8 8i)-(5 -4i)

40 32i -40i – 32

72 -8i

inner:

4. just a subtraction/distribution problem, you have to distribute the minus sign,

The FOIL technique. First, outdoors, interior, final. in simple terms like numerous different polynomial simplification. of direction i = (-a million). So it is going to look like this: First outdoors interior final (4)(5) (4)(-7i) (3i)(5) (3i)(-7i) = 20 28i 15i 21i = 20 13i 21 = 40-one 13i (simplified)

This post is last updated on hrtanswers.com at Date : 1st of September – 2022