Water at a gauge pressure of 3.8 atm at street level [Solved]

1atm = 1.853454Pa
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flow velocity1.7 m/s
pressure = 1.85atm

By continuity equation:
v2 = (A1v1) / A2 = (d1/d2)v1 = (4.2/2.6)* 0.65 = 1.7 m/s

By Bernoullis Equation:
P1 gh1 (v1)= P2 gh2 (v2)
[v1 -v2] /2 = (P2-P1)/ g(h2 -h1)
(0.65- 1.7)/2 = (P2-P1)/ 1000 9.8*20
-1.23375= (P2-P1)/ 1000 196
(P2-P1) = 197233.75 Pa
P2 = P1-197233.75, P1 = 3.8atm = 385035 Pa
P2 = 385035-197233.75 = 187801.25 Pa ( gauge pressure)

1atm = 1.853454Pa
=======================
flow velocity1.7 m/s
pressure = 1.85atm

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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