# What is the amplitude of the oscillating electric and magnetic field in the laser beam [Solved] A typical helium-neon laser found in supermarket checkout scanners emits 633-nm-wavelength light in a 1.2mm diameter beam with a power of 1.5mW . Thanks in advance!

Answers E = 1.0 MV / m B = 11 pT
The amplitudes of the electric and magnetic fields in the laser beam can be
obtained from the intensity of the beam for the electric field
I = Ea / [ 2 c ] > Ea = 2 c I > Ea = [ 2 c I ] where
I = P / [ r ] = P / [ ( d ) ] = P / [ d ] = 4 P / [ d ]
where d = beam diameter that is
I = 4 ( 1.5 10 W ) / [ ( 1.2 10 m ) ] = 1326 W / m so that in
SI system Ea = [ 2 c I ] = [ 2 ( 4 10 ) ( 3 10 ) ( 1326 ) ]
= 1.0 10 N / C = 1.0 10 V / m = 1.0 MV / m
And since Ea / Ba = c > Ba = Ea / c = { [ 2 c I ] } / c = [ 2 I / c ]
Ba = [ 2 ( 4 10 ) ( 1326 ) / ( 3 10 ) ]
.. = 1.11 10 T = 11 pT

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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