# What is the fundamental frequency of the steel wire in the figure [Solved]

L = 2m * 2 = 2.828 m
velocity = sqrt ( tension / mass per unit length )
f1 = velocity / 2L
tension 8 * 9.8 = 78.4 N
mass per unit length = 75 g / 2.828 = 26.52 g / m
v = 78.4 / 0.02652 = 54.37 m/s
f1 = velocity / 2L = 54.37 / 2.828 * 2 = 9.613 Hz

can you please email me how you got the answer to this question. ive been looking all over and cant find it.
my final is this week! i could really use the help
thanks

can you please email me how you got the answer to this question. ive been looking all over and cant find it.
my final is this week! i could really use the help
thanks

can you please email me how you got the answer to this question. ive been looking all over and cant find it.
my final is this week! i could really use the help
thanks

can you please email me how you got the answer to this question. ive been looking all over and cant find it.
my final is this week! i could really use the help
thanks

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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