# what is the ionic equation for the reaction HBr(aq) NH3(aq)Yield NH4Br(aq) [Solved] RE:
what is the ionic equation for the reaction HBr(aq) NH3(aq)Yield NH4Br(aq)

HBr is a strong acid : HBr = H Br-
NH4Br is a strong salt : NH4Br = NH4 Br-

RE:
what is the ionic equation for the reaction HBr(aq) NH3(aq)Yield NH4Br(aq)

H Br- NH3 = NH4 Br-

HBr is a strong acid : HBr = H Br-
NH4Br is a strong salt : NH4Br = NH4 Br-

H NH3 = NH4

NaOH Ag(NO)3 AgOH Na(NO)3 already balanced so no balancing required now write it in ionic form like this: Na (aq) OH (aq) Ag (aq) (NO)3 (aq) AgOH (s) Na (aq) (NO)3 (aq) [AgOH is insoluble so will be a precipitate] Now to get the net ionic equation write it again BUT leave out common ions that are on both sides of the equation: Ag (aq) OH (aq) AgOH (s) btw for this one the middle step really isnt needed the final net ionic equation could just be written straight down

Br- is a spectator ion so the net ionic is

RE:
what is the ionic equation for the reaction HBr(aq) NH3(aq)Yield NH4Br(aq)