What is the magnitude of the current in the loop [Solved]

The induced emf = /t = B*A/t

From another question Im assuming the loop has sides = 5.00 cm

complicated factor. seek into a search engine. just that can help!

The induced emf = /t = B*A/t

here A/t = L*v = 0.050m*50m/s = 2.5m2/s

complicated factor. seek into a search engine. just that can help!

so = B*2.5 = 0.20*2.5 = 0.50V

so I = V/R = 0.50V/0.50 = 1.0A

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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