What is the mass of 1.56 x 1021 atoms of magnesium in grams [Solved]

(6.02X10^23)X24.3=1.46286X10^25

mass of magnesium is 0.0629g

1 Mole of Mg is 24.3g.

1 Mole of Mg is 24.3g.

1.56X1021/1.46286X10^25=

m=0.00259 x 24.3= 0.0629g of Mg

mass of magnesium is 0.0629g

To work out the mass of 1.56 x 10^21 atoms of magnesium is grams is split into 2 parts first we have to convert the number of atoms into the number of moles and we do that using this formula
n=N/NA
n=number of moles
N=molecules of substance
NA=avogadros number which is 6.02 x 10^23

mass of magnesium is 0.0629g

then to work out the mass you have to multiply the number of mole(n)
by the molar mass(M) of magnesium which is 24.3
m=n x M
m=mass
n=number of moles
M=molar mass

m=0.00259 x 24.3= 0.0629g of Mg

1.5610^21 atoms x (1 mol / 6.02210^23 atoms ) = 2.5910^-3 moles

1.09X10^-22g

1.56X1021/1.46286X10^25=

1.09X10^-22g

(6.02X10^23)X24.3=1.46286X10^25

mass of magnesium is 0.0629g

This post is last updated on hrtanswers.com at Date : 1st of September – 2022

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