# What is the total number atoms in 0.111 mol of Fe(CO)3(PH3)2 [Solved]

1.665 moles x 6.0210^23 atoms/mole = 1.0010^24 atoms in .111 mole of Fe(CO)3(PH3)2

Moles Fe = 0.111
moles C = 3 x 0.111 = 0.333
moles O = 3 x 0.111 = 0.333
moles P = 2 x 0.111 = 0.222
moles H = 6 x 0.111 = 0.666
total moles = 1.67
atoms = 1.67 x 6.02 x 10^23=1.00 x 10^24

Yup you do need Avogadros number, which is 6.02210^23 particles/mole so we can use this to get rid of moles as our unit, heres how. In each molecule we have 1 Fe, 3 C, 3 O, 2 P, and 6 H. So this means that we have 0.111 mol Fe, 0.333 mol C, 0.333 mol O, 0.222 mol P and 0.666 mol H. Now we can use Avagadros number.
0.111 mol Fe(6.02210^23 Fe atoms/mol Fe)=6.6810^22 Fe atoms. Do this for each element to get
2.0010^23 atoms of C, 2.0010^23 atoms of O, 1.3410^23 atoms of P, and 4.0110^23 atoms of H. To get the total number of atoms we add up all of our numbers to get
1.0010^24 atoms.

Figure out the molar mass of this compound and mutliply by the number of mol so 0.1111 and then mutliply it by avaogardros number.

Moles Fe = 0.111
moles C = 3 x 0.111 = 0.333
moles O = 3 x 0.111 = 0.333
moles P = 2 x 0.111 = 0.222
moles H = 6 x 0.111 = 0.666
total moles = 1.67
atoms = 1.67 x 6.02 x 10^23=1.00 x 10^24

Figure out the molar mass of this compound and mutliply by the number of mol so 0.1111 and then mutliply it by avaogardros number.

This post is last updated on hrtanswers.com at Date : 1st of September – 2022