calculate the unknown value of the capicitor and voltage below capacitance is : 3uF voltage 20 volts you answered your own question. Unless you want the charge, which you didnt say Q = CV = 60uC
Z = 1/(C) C = 1/(Z)
= 2*15000 = 94247.78 rad/s
Z = sqrt(2)*6/0.065 = 130.54
C = 8.1278E-8 F
so the peak voltage is 6*sqrt(2) when the peak current is 6.5e-2 A and the impedance is 600*sqrt(2)/6.5 ohms = 1/w/C
C= 6.5/2/pi/1.5e4/600/sqrt(2)
calculate the unknown value of the capicitor and voltage below capacitance is : 3uF voltage 20 volts you answered your own question. Unless you want the charge, which you didnt say Q = CV = 60uC
calculate the unknown value of the capicitor and voltage below capacitance is : 3uF voltage 20 volts you answered your own question. Unless you want the charge, which you didnt say Q = CV = 60uC
calculate the unknown value of the capicitor and voltage below capacitance is : 3uF voltage 20 volts you answered your own question. Unless you want the charge, which you didnt say Q = CV = 60uC
how do you find Z though
This post is last updated on hrtanswers.com at Date : 1st of September – 2022