2. Change 36.8 g of CH3OH to moles

36.8 g CH3OH (1 mol CH3OH / 32 g CH3OH) = 1.15 mols CH3OH

Ok, the equation to find molarity (M) is:

Molarity = (moles of solute) / (liters of solvent)

The question gives us 2 of the 3 things we need:

Molarity = 0.500 M

Moles = the question gives us 36.8 g, but we can change that to moles

1. Find the molar mass (MM) of CH3OH

MM = (1 *12) (4 * 1) (1 * 16)

MM = 32

2. Change 36.8 g of CH3OH to moles

36.8 g CH3OH (1 mol CH3OH / 32 g CH3OH) = 1.15 mols CH3OH

3. Find the liters of solvent (x)

0.500 M = (1.15 mols CH3OH) / (x L)

(0.500 M) / (1.15 mols CH3OH) = x L

x L = 0.4347826087 L

To the correct number of significant figures: x L = 0.435 L

the guy above me did everything correct except the last part.. its 1.15/0.500 which equals 2.30 L. NOT .500/1.15! 0.435 is wrong!

This post is last updated on hrtanswers.com at Date : 1st of September – 2022